Question

Let logb(2) = 0.3869, logb(3) = 0.6131, and logb(5) = 0.8982. Using these values, evaluate logb(6).

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Answer 1

Answer:

Are the numbers in brackets base of log or bracket means multiply ?

Answer 2

The value of $log_b(6)$ is 1.

Step-by-step explanation:

Given information: $\log_b(2)=0.3869,\log_b(3)=0.6131,\log_b(5)=0.8982$

Using the given values we need to find the value of $log_b(6)$.

$log_b(6)=log_b(2\times 3)$

Using the properties of logarithm

$log_b(6)=log_b(2)+\log_b(3)$         $[\because log_a(mn)=log_am+log_an]$

Substitute the given values.

$log_b(6)=0.3869+0.6131$

$log_b(6)=1$

Therefore, the value of $log_b(6)$ is 1.

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