Question

Let m be the mid-point and 1 be the lower class limit of a class in a continuous frequency distribution. The upper class limit of the class is​

Answer 1

Answer:

given , mid point = m

lower class limit = 1

let upper class limit be x

then , according to formula ;

m = (1 + x) / 2

2m = 1 + x

x = 2m - 1

Step-by-step explanation:

Answer 2

Answer:

2m – l

Step-by-step explanation:

Let m be the mid point and L be the lower class limit of a class in a continuous frequency distribution the upper class limit of the class is

(b) Let x and y be the lower and upper class limit of a continuous frequency distribution. Hence, the lower class limit of the class is 2m – l.