Question

let m be the mid point and l be the upper class limit of a class in a continuous frequency distribution. the lower limit of the class is?

Answer 1

give a class interval and frequency

Answer 2

$hey\: mate \:here \: is \: ur\: required\: answer \\ \\ let \: x = lower \: class\: limit \\ \\ let \:y = upper\: class\: limit\\ \\ let\: m = midpoint \\ \\ we\: know\: that \\ \\ \frac{(x + l)}{2} = m \\ 2m \: = \: x + l \\ x = 2m - l$

hence this is the required answer

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