Question

Let M be the middle point of the chord PQ of a circle. If AB be any other chord through M
then prove that PQ <AB.​

Answer 1

Answer:

hope you get your answers

Answer 2

proved

PQ <AB.​

Step-by-step explanation:

let C(0,r) be the circle

let M be the point within it

Let PQ be the chord whose mid point is M

let AB be another chord through M .

we have to prove that PQ < AB

construction : join OM , draw ON ⊥ AB

now , in right triangle OMN , OM is the hypotenuse

therefore

OM >ON

chord AB is nearer to O  in comparison to PQ

thus

PQ < AB

Hence , proved

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