Question

Let M be the sum of all possible 4 digit numbers with different digits formed from
digits 1, 2, 3, 4. Let N be the sum of all possible 4 digit numbers with different digits
formed from digits 2, 4, 6, 8. Find the value of

N/M


please give explanation too​

Answer 1

Answer:

Given:

Selling every article at loss 10/-

Loss = 16 ⅔ = 50/3

Loss % = 50/3%

Find:

Cost of each article?

Solution:

Let cost of article be 'A'

50/3 × 1/100 × A = 10

50/300 × A = 10

\begin{gathered}: { \implies{ \sf{ \frac{50}{300} A =10 }}} \\ \\ : { \implies{ \sf{ 50A =3000 }}} \\ \\ : { \implies{ \sf{ A = \frac{3000}{50} }}} \\ \\ : { \implies{ \sf{ A = \frac{{ \cancel{3000}}}{ \cancel{{50}}} }}} \\ \\ : \:{ \implies{ \sf{ \red{ A = 60 }}} }\end{gathered}

:⟹

300

50

A=10

:⟹50A=3000

:⟹A=

50

3000

:⟹A=

50

3000

:⟹A=60

{ \therefore{ \sf{ \underline{ \blue{Cost \: of \: Each \: Article = 60rs}}}}}∴

CostofEachArticle=60rs

Answer 2

5545 is the answer

Please mark me as brainliest