Question

Let m = tan 3 and n = sec 6, then which of the following statement(s) does/do not hold good ?
(A) m&n both are positive
(B) m&n both are negative
(C) m is positive and n is negative
(Dym is negative and n is positive

Answer 1

Answer:

C is correct answer

Because value of tan lie between 0- 1 it is always positive

And sec is negative in somecase

Answer 2

Answer: A, B and C

Step-by-step explanation:

m= tan3. n = sec6

π = 3.14

π/2 = 1.57

Since tan3 lies in 2nd quadrant, so tan3 is negative.

n = sec6

3π/2= 4.71

2π= 6.28

Since sec6 lies in 4th quadrant, so it is positive...

So A,B and C options do not hold good...

HOPE IT HELPED...