Question

let me answer immediately plz

Answer 1

Convert the units from MKS to CGS:

$1n \: = {10}^{5} \: dyne \\ \\ 1m = 100 \: cm \\ \\ 1kg = 1000g$

$1 \: \: \frac{n. {m}^{2} }{kg} \\ \\ = 1 \times \frac{ {10}^{5} \: dyne \times {(100 \: cm)}^{2} }{1000 \: g}$

$= 1 \times \frac{ {10}^{5} \: dyne \times { {10}^{4} \: cm}^{2} }{ {10}^{3} \: g} \\ \\ = 1 \times \frac{ {10}^{5} \times {10}^{4} }{ {10}^{3} } \: \frac{dyne. {cm}^{2} }{g}$

$= {10}^{6} \: \frac{dyne. {cm}^{2} }{g}$

Now, convert G into CGS system:

$6.67 \times {10}^{11} \frac{n. {m}^{2} }{kg} \\ = 6.67 \times {10}^{11} \times {10}^{6} \: \frac{dyne. {cm}^{2} }{g} \\ = 6.67 \times {10}^{17} \: \frac{dyne. {cm}^{2} }{g}$

Answer 2

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Convert the units from MKS to CGS:

$1n \: = {10}^{5} \: dyne \\ \\ 1m = 100 \: cm \\ \\ 1kg = 1000g$

$1 \: \: \frac{n. {m}^{2} }{kg} \\ \\ = 1 \times \frac{ {10}^{5} \: dyne \times {(100 \: cm)}^{2} }{1000 \: g}$

$= 1 \times \frac{ {10}^{5} \: dyne \times { {10}^{4} \: cm}^{2} }{ {10}^{3} \: g} \\ \\ = 1 \times \frac{ {10}^{5} \times {10}^{4} }{ {10}^{3} } \: \frac{dyne. {cm}^{2} }{g}$

$= {10}^{6} \: \frac{dyne. {cm}^{2} }{g}$

Now, convert G into CGS system:

$6.67 \times {10}^{11} \frac{n. {m}^{2} }{kg} \\ = 6.67 \times {10}^{11} \times {10}^{6} \: \frac{dyne. {cm}^{2} }{g} \\ = 6.67 \times {10}^{17} \: \frac{dyne. {cm}^{2} }{g}$