Let me divide ₹170 among x,y and z in such a way that y gets ₹30 less than twice the amount x gets and z gets ₹ 15 more they half the amount y gets. Let's find how much money each gets.
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Total amount = Rs. 170
∴Let y be (2x - 30)
Let z be {1/2(2x - 30) + 15}
∴ ATP,
x + (2x - 30) + {1/2 (2x - 30) + 15} = 170
=> x + 2x - 30 + x - 15 + 15 = 170
=> 4x - 30 = 170
=> 4x = 170 + 30
=> 4x = 200
=> x = 200/4
=> x= 50
∴ x gets = Rs. 50
y gets = Rs. (2 × 50 - 30)
= Rs. 70
and, z gets = Rs. {1/2 (2 × 50 - 30) + 15}
= Rs. 50
HOPE THIS HELPS! :)
∴Let y be (2x - 30)
Let z be {1/2(2x - 30) + 15}
∴ ATP,
x + (2x - 30) + {1/2 (2x - 30) + 15} = 170
=> x + 2x - 30 + x - 15 + 15 = 170
=> 4x - 30 = 170
=> 4x = 170 + 30
=> 4x = 200
=> x = 200/4
=> x= 50
∴ x gets = Rs. 50
y gets = Rs. (2 × 50 - 30)
= Rs. 70
and, z gets = Rs. {1/2 (2 × 50 - 30) + 15}
= Rs. 50
HOPE THIS HELPS! :)
CoolixirPratt:
Welcome! :)
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