Let me get the answer of this question please..
Attachments:
Answers
Answered by
3
This is the answer
plz thank me in my profile
plz thank me in my profile
Attachments:
manasarech:
R u 10th
It was given that, a cos ∅ - b sin ∅ = c and to prove, a sin∅ + b cos ∅ = √a²+b²-c².
But you interchanged it
Sorry
Answered by
2
a cos ∅ - b sin ∅ = c
( a cos ∅ - b sin ∅ )² = c²
a²cos²∅ + b²sin²∅ - 2abcos∅sin∅ = c²
a²(1-sin²∅) + b(1-cos²) - 2 abcos∅sin∅ = c²
a²-a²sin∅ + b² - b²cos²∅ - 2abcos∅sin∅ = c²
a²+b²-c²=a²sin²∅ + b²cos²∅+ absin∅cos∅=c²
a² + b² - c² = (asin∅ + b cos∅)²
√a² + b² - c² = √(asin∅ + b cos∅)²
asin∅ + bcos∅ = √a² + b² - c²
Hence proved.
Hope it may help you!!!!
Plz mark as brainlest!!!!!
( a cos ∅ - b sin ∅ )² = c²
a²cos²∅ + b²sin²∅ - 2abcos∅sin∅ = c²
a²(1-sin²∅) + b(1-cos²) - 2 abcos∅sin∅ = c²
a²-a²sin∅ + b² - b²cos²∅ - 2abcos∅sin∅ = c²
a²+b²-c²=a²sin²∅ + b²cos²∅+ absin∅cos∅=c²
a² + b² - c² = (asin∅ + b cos∅)²
√a² + b² - c² = √(asin∅ + b cos∅)²
asin∅ + bcos∅ = √a² + b² - c²
Hence proved.
Hope it may help you!!!!
Plz mark as brainlest!!!!!
Similar questions