Let me know the integration of tanxcotx
solve this for me
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Answered by
2
y=∫tanx/cotx dx
=∫tan²x dx
=∫(sec²x-1)dx
y=tanx-x+c
PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER.
=∫tan²x dx
=∫(sec²x-1)dx
y=tanx-x+c
PLEASE MARK MY ANSWER AS A BRAINLIEST ANSWER.
arnav8495:
reply plz
Answered by
0
INTEGRAL(tanx/cotx)dx=INTEGRAL(cosx/sinx/sinx/cosx)dx=INTEGRAL(cosx^2/sinx^2)dx=INTEGRAL(1-sinx^2/sinx^2)dx=INTEGRAL[(1/sinx^2 - 1)]dx=INTEGRAL[d(tanx) - x]dx=TANX -X +C,where c constant real number.
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