Question

Let n! = 1 x 2 x 3 x 4 x ... x n for integer n 2 1. What could be the value of 1! + (2 x 2!)
+ (3 x 3!) + (4 x 4!) + ... (10 x 10!)?

Answer 1

Answer:

11!-1

Step-by-step explanation:

you use the n×n! = (n+1)! -n! rule