Math, asked by jhahim11, 1 year ago

Let N = 5^2019 – 1, then N is
(A) divisible by 4 and 6 but not divisible by 31
(B) divisible by 4 and 31 but not divisible by 6
(C) divisible by 6 and 31 but not divisible by 4
(D) divisible by all 4, 6 and 31

Answers

Answered by brunoconti

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

Attachments:

jhahim11: can you explain me the trick behind it in some detail as i am unable to understand your answer properly

brunoconti: i am using congruences. if x is congruent to r modulo p means that the remainder upon division of x by p is r. example 25 = 4×6 + 1 means that 25 is congruent 1 modulo 4 or 6. then there are some rules regarding congruences

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Let N = 5^2019 – 1, then N is (A) divisible by 4 and 6 but not divisible by 31 (B) divisible by 4 and 31 but not divisible by 6 (C) divisible by 6 and 31 but not divisible by 4 (D) divisible by all 4, 6 and 31

Answers

Let N = 5^2019 – 1, then N is
(A) divisible by 4 and 6 but not divisible by 31
(B) divisible by 4 and 31 but not divisible by 6
(C) divisible by 6 and 31 but not divisible by 4
(D) divisible by all 4, 6 and 31