Question

Let N=98, 89.5-99.5 is the median class size of the class is 10,frequency of median class is 30and it's cumulative frequency is 40.Find the median of the data​

Answer 1

The median of the data is 92.5

Step-by-step explanation:

We know that

$\boxed{\text{Median}=l+\frac{\frac{n}{2}-cf}{f}h}$

Where,

l = lower limit of median class = 89.5

n = no. of observations = 98

cf = cumulative frequency of preceding classes = 40

f = frequency of median class = 30

h = class interval = 10

Therefore,

$\text{Median}=89.5+\frac{\frac{98}{2}-40}{30}\times 10$

$\implies \text{Median}=89.5+\frac{49-40}{3}$

$\implies \text{Median}=89.5+\frac{9}{3}$

$\implies \text{Median}=89.5+3$

$\implies \text{Median}=92.5$

Hope this answer is helpful.

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