Question

LET N =98, 89.5-99.5 is the median class , size of the class is 10 , frequency of median class is 30 and its cumulatively frequency is 40.find the median of the data​

Answer 1

$Given \: N = 98, \\Median \:class = 89.5 - 99.5 ,\\Lower \: boundary \: of \: median \:class (l) = 89.5 \\Size\:of \:the \:class (h) = 10 , \\Frequency \:of \: median \:class (f) = 30, \\Cumulative \: frequency (c.f) = 40$

$\boxed { \pink { Median= l + \Big(\frac{\frac{N}{2} - c.f}{f}\Big) \times h }}$

$\implies m = 89.5 + \Big( \frac{\frac{98}{2} - 40}{30} \Big) \times 10 \\= 89.5 + \frac{ 49 - 40 }{3} \\= 89.5 + \frac{9}{3} \\= 89.5 + 3 \\= 92.5$

Therefore.,

$\red{ Median } \green {= 92.5 }$

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