Question

let N be greatest number that will divide 1305,4665,6905 leaving the same remainder in each case.then, sum of the digits in N is​

Answer 1

Answer:

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: [A]. = H.C.F. of 3360, 2240 and 5600 = 1120

Answer 2

Answer:

4

Step-by-step explanation:

We have to find the greatest number N that will divide 1305, 4665 and 6905 leaving the same remainder. The greatest number N is the H.C.F of (4665 – 1305), (6905 – 4665) and (6905 – 1305). So the greatest number N is the H.C.F of 3360, 2240 and 5600 leaving the same remainder.