Question

Let N be the 8th term of the sequence 1440, 1716, 1848, whose terms are formed by multiplying the corresponding terms of an arithmetic progression Find 12 N​

Answer 1

Answer:

Let a be the first term and d be their common difference of the AP.

Then, nth term of the AP T

n

=a+(n−1)d

Given, 8×T

8

=12×T

12

⇒8(a+(8−1)d)=12(a+(12−1)d)

⇒8(a+7d)=12(a+11d)

⇒2(a+7d)=3(a+11d)

⇒2a+14d=3a+33d

⇒a=−19d

So, T

20

=a+(20−1)d=−19d+19d=0

Step-by-step explanation:

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Answer 2

answer is this did you understood or can I explain