Question

Let N be the greatest number that will divide 1305, 4664 and 6905
leaving the remainders 5,10,2 respectively. The sum of the digits in N
is​

Answer 1

Step-by-step explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Answer 2

Answer:

The sum of digits is (1+1+0+2) = 4.