Let n be the greatest number that will divide 148, 246 and 623 leaving remainders 4, 6 and 11 respectively. what is the remainder if n is divided by 7?
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We know that When a greatest number that divide x,y,z and leaves remainder a,b,c respectively = HCF of (x - a),(y - b),(z - c).
Now,
HCF of (148 - 4),(246 - 6),(623 - 11)
= > HCF of (144, 240,612)
Prime factorization of 144 = 2 * 2 * 2 * 2 * 3 * 3
Prime factorization of 240 = 2 * 2 * 2 * 2 * 3 * 5
Prime factorization of 612 = 2 * 2 * 3 * 3 * 17
HCF(144,240,612) = 2 * 3 * 3 = 12.
Hence, the greatest number is n = 12.
Now,
We have to find the remainder when n is divided by 7.
= > 7)12(1
7
---
5.
Therefore, the remainder is 5.
Hope this helps!
siddhartharao77:
:-)
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