Question

Let n(U)=700,n(A)=200,n(B)=300 and n(AnB)=100 then what is n(A'nB')?

Answer 1

Answer:

Correct option is

C

300

Ans. (c).n(A∩B)=n(A∪B)

=n(u)−n(A∪B)

=n(u)−{n(A)+n(B)−n(A∩B)}

=700−{200+300−100}=300