Let n1 < n2 < n3 < n4 < n5 be positive integers such that n1 + n2 + n3 + n4 + n5 = 20. Then the number of such distinct arrangements (n1, n2, n3, n4, n5) is
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YOUR SOLUTION IS IN THE ATTACHMENT
#KEVIN
HOPE IT HELPS YOU ☺
TRY TO MARK IT AS BRAINLIEST!!!
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