Question

Let nr and nb be respectively the number of photons emitted by a red bulb and a blue bulb of equal power in a given time.

Answer 1

Check this attachment :-)

Answer 2

The number of photons emitted by a red bulb and a blue bulb of equal power in a given time is given by nr>nb

1. The formula for power generated by a photo is
2. P = nhf ,here P is the power ,n is no of photons,h is Planck's constant and f is the frequency
3. Let the frequency of the photon released by red is fr and by blue bulb is fb
4. As we know that the frequency of the red light is less than the frequency of blue (fb>fr)
5. As per the the question Power is same from both the bulb so we can write
6. nrfrh=nbfbh
7. h cancels out both side so now , nr/nb=fb/fr
8. as fb/fr>1 so nr/nb>1
9. so nr>nb