Question

Let nr and nb be the number of photons emitted by a red bulb and a blue bulb, respectively, of equal power in a given time.
(a) nr = nb
(b) nr < nb
(c) nr > nb
(d) The information is insufficient to derive a relation between nr and nb.

Answer 1

Let nr and nb be the number of photons emitted by a red bulb and a blue bulb, respectively, of equal power in a given time are nr > nb.

Explanation:

• The power of the two bulbs are equal. Energy per unit time is equal for both the bulbs.
• Red lights frequency is less than blue lights frequency.
• The photon energy of red light is less than the photon energy of blue light.
• The photon energy of blue light need more energy than the photon energy of red light.
• The energy in the two bulbs are equal for particular time, then 'the number of photons of red light is greater than the number of photons of blue light'.
• The energy emits in the two bulbs are equal.
• According to visible light, the wavelengths are increased in the order of VIBGYOR.
• Blue light has less wavelength than the red light.

To learn more;

1. https://brainly.in/question/5332963
2. https://brainly.in/question/9095065

Answer 2

Let nr and nb be the number of photons emitted by a red bulb and a blue bulb, respectively, of equal power in a given time is $n_{r}>n_{b}$.

Explanation:

• When two bulbs consume equal amount of energy per unit time, they are seen to be of equal power. More than the red light’s frequency (fr), the blue light’s frequency (fb) is higher. If this is the case, $\mathrm{hfr}<\mathrm{hfb}$.
• So, the blue light photon’s energy is more than the red light’s photon’s energy.  
• From the two bulbs, the amount of emitted energy is the same. So$n_{r}>n_{b}$,