Let o be an acute angle in a right triangle explain why sin(0)=cos(90 degrees-0)
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Answer:
because we can that sinA is equal to cos(90-A).
so sin0 is equal to cos90 ....hope u like it
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Given : θ be an acute angle in a right triangle
To find : explain why sin(θ)=cos(90°-θ)
Solution:
in a Right angle triangle
we know
Sin θ = Perpendicular / Hypotenuse
Cosθ = Base / Hypotenuse
Now for other acute angle let say α
Base & perpendicular get change
Hence
Cos α = Sin θ
now in a triangle sum of all angles = 180°
one angle in right angle = 90°
=> α + θ + 90° = 180°
=> α = 90° - θ
=> Cos(90° - θ) = Sin θ
Hence Sin θ = Cos(90° - θ)
Learn more:
cosec(90+x)+cot(90+x)/cosec(90-x)+tan(180-x)+tan(180+x)+
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