Question

let o be centre of circle ABC if bisector ad of angle bac passes through O prove that triangle abc is an isosceles triangle​

Answer 1

Answer:

Given that ∠OAB = ∠OAC (AD bisects ∠BAC) -- (1) 

Since O is the center of the circumcircle of triangle ABC, OA = OB = OC

=> OA = OB, OA = OC and OB = OC

=> ∠OAB = ∠OBA, ∠OAC = ∠OCA  and ∠OBC = ∠OCB -- (2)

From (1) and (2)

∠OAB = ∠ OAC = ∠ OBA = ∠OCA -- (3)

Now ∠ABD = ∠OBA + ∠OBC

= ∠OCA + ∠OCB [Using (2) and (3)]

= ∠ACD

=> ABC  = ∠ACB

So AB = AC

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Answer 2

Answer:

Ab=Ac

Step-by-step explanation:

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