Question

Let O be the centre of a circle of radius 1, P and Q are the points on the circle such that θ=∠POQ is an acute angle and R is a point outside the circle such that OPRQ is a parallelogram. If the area of the part of the parallelogram that is outside the circle is f(θ), then limθ→0 ​θ/f(θ)​ is equal to.. Solve this pls

Answer 1

Answer:

Let O be the centre of a circle of radius 1, P and Q are the points on the circle such that θ=∠POQ is an acute angle and R is a point outside the circle such that OPRQ is a parallelogram. If the area of the part of the parallelogram that is outside the circle is f(θ), then limθ→0 θ/f(θ) is equal to.. Solve this pls

Answer 2

$\huge\mathbb\blue{ANSWER}$

$\huge\boxed{\fcolorbox{blue}{red}{3/π}}$

$lim_{0} = \binom{f(0)}{0} = \frac{3}{\pi}$

SO, THE ANSWER IS

$\frac{3}{\pi}$

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