Question

Let O is the centre of the circle. Find <AOB and <ACB​

Answer 1

Answer:

∠AOB  = 60° where o is the centre of a circle and angle ACB=30°

Step-by-step explanation:

o is the centre of a circle

∠AOB  = Angle subtended by arc/Chord  AB at Center

∠ACB = Angle subtended by arc/Chord  AB  at arc segment

Angle subtended by arc/Chord  AB at Center = 2 (Angle subtended by arc/Chord  AB  at arc segment)

=> ∠AOB  =  2 ∠ACB

=> ∠AOB  =  2 * 30°

=> ∠AOB  = 60°

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Answer 2

angle AOB= 150.......