Question

Let oa =a , ob =10a+2b, oc =b and o is the origin let p denote the area of quadrilateral oabc and q denote the area of parallelogram prove that p=6q

Answer 1

Answer:

6

Step-by-step explanation:

q=area of parallelogram wih OA and OC as adjacent sided =∣OA×OC∣

=∣a×b∣

and

p= area of quadrilateral OABC

=(

2

1

)∣OA×OB∣+(

2

1

)∣OB×OC∣

=(

2

1

)∣a×(10a+2b)∣+(

2

1

)∣(10a+2b)×b∣

=∣a×b∣+5∣a×b∣=6∣a×b∣=6q

Thus K=6