Let P=(0,0,1),Q=(1,−1,1),R=(−2,1,−1). Find
(a) The area of the triangle PQR.
area =
(b) The equation for a plane that contains P, Q, and R.
This plane is
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Answer:
Area=
2
1
[x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)]
By substituting the values we get,
=
2
1
[−1(5−2)+0(2−1)+3(1−5)]
=
2
1
[−1(3)+0+3(−4)]
=7.5 sq units
Step-by-step explanation:
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