Question

Let P=1×1!+2×2!+3×3!+.…+999×999! Find the remainder when p+1 is divided by 1000! Pls answer, will mark as brainliest

Answer 1

Answer:

Step-by-step explanation:

We have,                 y= [p(p2+3p+1)]13    

putting p=999 in above polynomialy=

 

[999 (9992+3(999)+1]13

=[999(998001+2997+1)]13

=[999×1000999]13

=999−−−√3×1000999−−−−−−−

√3=9.996×100.03=999.89 Answer