Question

Let P = 2^3·3^3·4^4·5^5·8^2·10^ 3, then the total number of divisors will be

Answer 1

Answer:

Step 1:- Convert all these no. In prime factors which will give you

Step 1:- Convert all these no. In prime factors which will give you 2^3×3^3×2^8×5^5×2^6×2^3×5^3.

Step 1:- Convert all these no. In prime factors which will give you 2^3×3^3×2^8×5^5×2^6×2^3×5^3.Step 2:- These will simplify to

Step 1:- Convert all these no. In prime factors which will give you 2^3×3^3×2^8×5^5×2^6×2^3×5^3.Step 2:- These will simplify to 2^20×3^3×5^8.which has only prime factor terms.

Step 1:- Convert all these no. In prime factors which will give you 2^3×3^3×2^8×5^5×2^6×2^3×5^3.Step 2:- These will simplify to 2^20×3^3×5^8.which has only prime factor terms.Step 3:- Now its a simple P&C question.So the answer would be (20+1)*(3+1)*(8+1)=756

please mark brainlist