let P =2^4×3^2×4^3×5^2×6^7 then the total number of divisors will be
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Total no of divisors = (4+1)(2+1)(3+1)(2+1)(7+1)
= 5 × 3 × 4 × 3 × 8
= 1440
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Answered by
6
Answer:
First of all convert everything into prime factors.
Like write 4^4 as 2^8
8^2 as 2^6
10^3 as 5^3 * 2^3
So you have find factors of
2^3 * 3^3 * 2^8 * 5^5 * 2^6 * 5^3 * 2^3
=2^20 * 3^3 * 5^8
Total factors will be
21 * 4 * 9 = 756.
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