Question

Let P (2,-4) and Q (3, 1) be two given points. Let R (x, y) be a point such that ( x-2)(x-3) + (y-1)
(y+4) = 0. If area of ∆PQR is 13/2, then the number of possible positions of R are​

Answer 1

Answer:

The number of possible positions of R are 2

They are (0,-1) and (5,-2)