Question

. Let P (6, -3) be the middle point of the line segment AB, where A has the coordinates (-2, 0). Find the coordinate of B.

Answer 1

Given ,

• The point P(6, -3) is the middle point of the line segment AB and A(-2,0)

As we know that , the mid point formula is given by

$\boxed{ \tt{x = \frac{ x_{2} + x_{1} }{2} \: , \: y= \frac{ y_{2} + y_{1} }{2} }}$

Let ,

The coordinate of B be " (x , y) "

Thus ,

6 = {x + (-2)}/2

12 = x - 1

x = 13

And

-3 = {y + (-3)}/2

-6 = y - 3

y = -3

Therefore , the coordinate of B is (13,-3)

Answer 2

Answer:

Let B(x,y) then

$\frac{ - 2 + x}{2} = 6 \: \: i.e \: \: - 2 + x = 12 \: \: so \: \: x = 14$

$\frac{y + 0}{2} = - 3 \: \: i.e \: \: y = - 6$

so B ( 14 , -6 ). Ans.