let p and q are the remainders when the polynomial x3 +2x2-5ax-7and x3+ax2-12x+6 are divided by x+1 and x-2 respectively if 2p+q=6 find a
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priyanshugola7:
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Answer:
a=2
Step-by-step explanation:
let f(x)= x3 +2x2-5ax-7
and g(x)= x3+ax2-12x+6
when f(x) is divided by x+1
the remainder is p
so f(-1)=p
(-1)^3+2(-1)^2-5a(-1)-7=p
-1+2+5a-7=p
p=5a-6--------------(1)
also when g(x) is divided by x-2
the remainder is q
g(2)=q
(2)^3+a(2)^2-12*2+6=q
8+4a-24+6=q
q=4a-10-------------(2)
No given that
2p+q=6
putting value from (1) and (2)
2*(5a-6)+4a-10=6
10a-12+4a-10=6
14a=6+12+10=28
a=28/14=2
a=2
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