Question

let p and q be real numbers satisfying p^2-q^2=4 and 2 pq=3 then(p^2+q^2) is equal ot

Answer 1

Answer:

Step-by-step explanation:

using formula (a+b)^2=(a-b)^2+4ab

(you can verify it)

so, from formula

(p^2+q^2)^2=(p^2-q^2)^2+4p^2q^2

(p^2+q^2)^2=(4)^2+4(pq)^2

(p^2+q^2)^2=16+4(3/2)^2        

(because 2pq=3 so pq=3/2)

(p^2+q^2)^2=16+9

(p^2+q^2)^2=25

(p^2+q^2)=5