Let p and q be two natural numbers.
5 p + 3 q + p q = 290.
Calculate q/p.
Easy question.
kvnmurty:
No guessing numbers. Use simple algebra
No. We need to find numerical values.but deriving algebraically
Answers
Answered by
3
Hey there!!
We are given ,
5p + 3q + pq = 290
add 15 on both the side i.e. RHS and LHS
so , => 15 + 5p + 3q + pq = 290 + 15
=> 5( 3 +p) + q ( 3 +p) = 305
=> ( 5 + q) ( 3+ p) = 305
Now we can express 305 as 5 ×61
( 5+q) (3+p) = 5×61
so, taking/comparing both the side
3 + p = 5
=> p = 2
also , 5 + q = 61
=> q = 56
A/q ,
q/p
=> 56/2 = 28
Hope this helps u users
^_^
We are given ,
5p + 3q + pq = 290
add 15 on both the side i.e. RHS and LHS
so , => 15 + 5p + 3q + pq = 290 + 15
=> 5( 3 +p) + q ( 3 +p) = 305
=> ( 5 + q) ( 3+ p) = 305
Now we can express 305 as 5 ×61
( 5+q) (3+p) = 5×61
so, taking/comparing both the side
3 + p = 5
=> p = 2
also , 5 + q = 61
=> q = 56
A/q ,
q/p
=> 56/2 = 28
Hope this helps u users
^_^
thanks.
:)
Answered by
1
ANSWER IS IN THE IMAGE
Attachments:
Similar questions