Let p be a prime number and a be a postive integer were p divides a^2 then show that p divides a
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HOLA !!
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HOPE U UNDERSTAND
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HOPE U UNDERSTAND
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Hey! ! !
Solution :-
☆ Let a=p1.p2.p3.p4.p5.....pn where, p1, p2, p3, ..., pn are prime numbers which are necessarily not distinct.
⇒a2=(p1.p2.p3.p4.p5.....pn).(p1.p2.p3.p4.p5......pn)
It is given that p divides a2. From the Fundamental theorem of Arithmetic, we know that every composite number can be expressed as product of unique prime numbers. This means that p is one of the numbers from (p1.p2.p3.p4.p5......pn).
We have a=(p1.p2.p3.p4.p5..pn) and p is one of the numbers from (p1.p2.p3.p4.p5......pn).
It means that p also divides a.
Hence, it is proved that if pdivides a2 then it also divides a.
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
Solution :-
☆ Let a=p1.p2.p3.p4.p5.....pn where, p1, p2, p3, ..., pn are prime numbers which are necessarily not distinct.
⇒a2=(p1.p2.p3.p4.p5.....pn).(p1.p2.p3.p4.p5......pn)
It is given that p divides a2. From the Fundamental theorem of Arithmetic, we know that every composite number can be expressed as product of unique prime numbers. This means that p is one of the numbers from (p1.p2.p3.p4.p5......pn).
We have a=(p1.p2.p3.p4.p5..pn) and p is one of the numbers from (p1.p2.p3.p4.p5......pn).
It means that p also divides a.
Hence, it is proved that if pdivides a2 then it also divides a.
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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