Math, asked by pratham154, 11 months ago

Let p be a prime number and a be a postive integer were p divides a^2 then show that p divides a

Answers

Answered by Anonymous
1
HOLA !!

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Refer the attachment

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Answered by Anonymous
1
Hey! ! !

Solution :-

☆ Let a=p1.p2.p3.p4.p5.....pn where, p1, p2, p3, ..., pn are prime numbers which are necessarily not distinct.

⇒a2=(p1.p2.p3.p4.p5.....pn).(p1.p2.p3.p4.p5......pn)

 

It is given that p divides a2. From the Fundamental theorem of Arithmetic, we know that every composite number can be expressed as product of unique prime numbers. This means that p is one of the numbers from (p1.p2.p3.p4.p5......pn).

 

We have a=(p1.p2.p3.p4.p5..pn) and p is one of the numbers from (p1.p2.p3.p4.p5......pn).

It means that p also divides a.

 

Hence, it is proved that if pdivides a2 then it also divides a.

☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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