Question

let P be the point (25, -5) and l be the line x + 3y+10=0 ? find perpendicular distance between P and l?​

Answer 1

Answer:

the perpendicular distance between the line x+3y+10=0 and the point (25, -5) is

= 25+3×(-5) +10÷√1^2+3^2

=2√10