Question

Let P denotes number of digits in 2^120 then find the value of P-31 (where log₁02=0.3010)


Don't spam ​

Answer 1

Answer:

the tenth Fibonacci number is Fib(10) = 55. The sum of its digits is 5+5 or 10 and that is also the index number of 55 (10-th in ...

Answer 2

log2000²⁰⁰⁰ =2000log2000=2000log(2×10³)

=2000[log2+3log10]

=2000[0.30103+(3×1)]

=6602.06

x=6602.06

When we take log with base 10, integer in answer shows one less than number of digits in number.

So, number of digits in number 2000²⁰⁰⁰=6602+1=6603