Question

let p of x is equals to x square minus four x plus three . Find the value of p(0), p(1),p(2),p(3) and obtain zeroes of the following zeroes of the following polynomial p(x)​

Answer 1

Answer:

Solution :

p(x) = x²-4x+3

i ) p(0) = 0²-4×0+3 = 3

ii ) p(1) = 1²-4×1+3 = 4-4 = 0

iii ) p(2) = 2²-4×2+3 = 7 - 8 = -1

iv ) p(3) = 3²-4×3 + 3 = 12 - 12 = 9

v ) p(x) = x²-4x+3

Let p(x) = 0

=> x²-4x+3 = 0

=> x² - x - 3x + 3 = 0

=> x( x - 1) - 3( x - 1 ) = 0

=> ( x - 1 )( x - 3 ) = 0

=> x -1 = 0 or x - 3 = 0

x = 1 or x = 3

Therefore ,

1 , 3 are zeroes of p(x)

Answer 2

Answer:

pls find the attached picture for the answer

Step-by-step explanation:

therefore 1and 3 are the zeroes of the polynomial p(x)

hope it helps you!