Question

Let p, q, r be three positive numbers such that p > q > r. when the smallest number is added to the difference of the rest two numbers, then the average of the resultant number and the original numbers except the smallest number is 21 more than the average of all the three original numbers. what would be the value of p - q?

Answer 1

no....................

Answer 2

Answer:

Step-by-step explanation:

[(r+p-q)+(p+q)]/3= (p+q+r)/3+21

r+p-q+p+q-p-q-r=63

p-q=63