Question

let p,q,r belongs to positive real numbers and 27pqr is greater than or equal to (p+q+r)^3 and 3p+4q+5r=12 then p^3+q^4+r^5 is equal to. a)3 b)6 c)2 d)1​

Answer 1

Step-by-step explanation:

27pqr≥(p+q+r)

3

⇒(pqr)

1/3

≥(

3

p+q+r

)

⇒p=q=r

Also 3p+4q+5r=12⇒p=q=r=1

p

3

+q

4

+r

5

=3

Hope this answer helpful to u

Answer 2

Answer:

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