let p,q, r, s be the positive rationals such that p+✓q=r+✓s then either p=r and q=s or b and d are squares of rationals
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Step-by-step explanation:
If a=c, then a+b=c+d⇒b=d⇒b=d
So, let a=c. Then, there exists a positive rational number x such that a=c+x.
Now,
⇒a+b=c+d
⇒c+x+b=c+d [∵a=c+x]
⇒x+b=d
⇒(x+b)2=(d)2
⇒x2+2bx+b=d
⇒b=2xd−x2−b
hope it helps uh!
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