Question

let p= tanø+secø then find the value of p+1/p​

Answer 1

Answer:

let

p= tanø+secø

1/ p= -tanø+secø

p+1/p=2 secø

Answer 2

Answer:

• p=tana+seca (: a instead of theta)
• p+1/p
• (tana+seca)+1/(tana+ seca)
• take LCM (: sec²a= 1 +tan²a)
• (tana+ seca)²+1/( tana+ seca)
• (tan ²a+sec ²a+ 2tana seca+1)/ (tana + seca)
• (1+tan²a+sec²a+2 tana.seca)/(tana+ seca)
• (sec²a+sec²a+2tana.seca)/( tana+seca)
• (2sec²a+2tana.seca)/(tana+ seca)
• bring out 2seca
• 2seca(seca+tana)/(tana+ seca)
• 2seca.