Question

Let p(x)=3x^3+4x^2-5x+8 find p(1)

Answer 1

$\huge \underbrace \mathfrak \red{Solution}$

$\huge \sf \longmapsto \: p(x) = {3x}^{3} + {4x}^{2} - 5x + 8 \\ \\ \huge \sf \longmapsto \: p(1) = {3(1)}^{3} + {4(1)}^{2} - 5(1) + 8 \\ \\ \huge \sf \longmapsto \: p(1) = 3 + 4 - 5 + 8 \\ \\ \huge \sf \longmapsto \: p(1) = 15 - 5 \\ \\ \huge \sf \longmapsto \: p(x) = 10$

Answer 2

Answer:

p(1)=3.1^3+4.1^2-5.1+8

=3.1+4.1-5.1+8

=3+4-5+8

=7-5+8

=2+8

=10