Let p(x) be a cubic polynomial such that coefficien
of xo is 1,p(1) = 1,p(2) = 2 and p(3) = 3, then the
value of p(4) is
(1) 4
(2) 6
3)1O
(4) 7
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A cubic polynomial P(x) is such that P(1)=1, P(2)=2, P(3)=3 and P(4)=5. The value of P(6) is:
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ANSWER
Given P(1)=1,P(2)=2,P(3)=3,P(4)=5
Let f(x)=(P(x)−x)
f(1)=P(1)−1=1−1=0
f(2)=P(2)−2=2−2=0
f(3)=P(3)−3=3−3=0
∴f(x)=0,x=1,2,3
⇒f(x)=a(x−1)(x−2)(x−3)
P(x)=a(x−1)(x−2)(x−3)+x
Put x=4
5=a(3)(2)(1)+4
⇒a=
6
1
∴P(x)=
6
1
(x−1)(x−2)(x−3)+x
∴P(6)=
6
1
(5)(4)(3)+6=16
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