Question

Let P(x ) be a polynomial such that P ( -1/2 ) = 0 ,then a factor of P( x ) is _____ *

2x - 1

2x + 1

x -1

x +1

​

Answer 1

Step-by-step explanation:

OPT B

2x+1

since p(-½)=0

so if q(x)= 2x+1

then

2x+1=0

2x=-1

x=(-½)

so option b is correct

Answer 2

A factor of P(x) is (2x + 1).

Step-by-step explanation:

Given that, $P(x)$ is such a polynomial that

$P(-\dfrac{1}{2})=0$

Let us take: $a=-\dfrac{1}{2}$

Then the required factor of $P(x)$ is

$x-a$

$=x-(-\dfrac{1}{2})$

$=x+\dfrac{1}{2}$

$=\dfrac{1}{2}(2x+1)$

So, the required factor is $(2x+1)$.

#SPJ3