Question

Let P(x) be a quadratic polynomial such that P(1) = P(-2): If -1 is
a root of the equation P(x) = 0, then the other root is

Answer 1

Answer:

4

Step-by-step explanation:

Let (x-a)(x-b) be the polynomial.

since

p(1)=p(2),

(1-a)(1-b)=(2-a)(2-b).

Implies a+b=3.

since p(-1) =0,

-1-a = 0 or -1-b = 0.

suppose -1-a = 0.

then a= -1,

and then -1+b = 3

b=4.

Then p(x)=(x+1)(x-4)

so other root is 4