Let p(x) =x^3+3x^2-6x+6 be divided by (x-1) find the remainder
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Solution:-
Given:-
- Polynomial :- ( x³ + 3x² - 6x + 6)
- Divident :- ( x - 1)
To Find:-
- Remainder :- ?
Find:-
x-1 = 0
=) x = 1
P(x) = x³ + 3x² - 6x + 6
=) P(1) = 1³ + 3(1)² -6 + 6
=) = 1 + 3
=) = 4.
Hence,
Remainder is 4.
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