Question

Let p(x) = x² – 4x + 3. Find the value of p(0), p(1), p(2), p(3) and obtain zeros of the polynomial p(x)​

Answer 1

p(0)=0-0+3

=3

p(1)=1-4+3

=0

p(2)=8-8(3)

=3

p(3)=9-12+3

=0

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Answer 2

Step-by-step Explaination :

• If x=0 , then , p(x)= x² - 4x + 3
• = 0² - 4×0 + 3
• = 0 - 0 + 3
• = 3
• If x=1, then , p(x) = x² - 4x + 3
• = 1² - 4×1 + 3
• = 1 - 4 + 3
• = -3 + 3
• = 0
• If x=2, then , p(x) = x² - 4x + 3
• = 2²+ 4×2 + 3
• = 4 + 8 +3
• = 15
• If x=3, then , p(x) = x² - 4x + 3
• = 3²- 4×3 + 3
• = 9 - 12 + 3
• = -3 + 3
• = 0

Answer :

Thus , p(0) = 3

p(1) = 0

p(2) = 15

p(3) = 0

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